r^2/3+r^1/3-12=0

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Solution for r^2/3+r^1/3-12=0 equation: 


r in (-oo:+oo)

(r^2)/3+(r^1)/3-12 = 0

(r^2)/3+r/3-12 = 0

1/3*r^2+1/3*r-12 = 0

DELTA = (1/3)^2-(-12*1/3*4)

DELTA = 145/9

DELTA > 0

r = ((145/9)^(1/2)-1/3)/(1/3*2) or r = (-(145/9)^(1/2)-1/3)/(1/3*2)

r = 3/2*((145/9)^(1/2)-1/3) or r = -3/2*((145/9)^(1/2)+1/3)

r in { -3/2*((145/9)^(1/2)+1/3), 3/2*((145/9)^(1/2)-1/3) }

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